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submitted 1 day ago* (last edited 1 hour ago) by AcesFullOfKings@feddit.uk to c/programmer_humor@programming.dev

A couple of years ago, my friend wanted to learn programming, so I was giving her a hand with resources and reviewing her code. She got to the part on adding code comments, and wrote the now-infamous line,

i = i + 1 #this increments i

We've all written superflouous comments, especially as beginners. And it's not even really funny, but for whatever reason, somehow we both remember this specific line years later and laugh at it together.

Years later (this week), to poke fun, I started writing sillier and sillier ways to increment i:

Beginner level:

# this increments i:
x = i 
x = x + int(True)
i = x

Beginner++ level:

# this increments i:
def increment(val):
   for i in range(val+1):
      output = i + 1
   return output

Intermediate level:

# this increments i:
class NumIncrementor:
	def __init__(self, initial_num):
		self.internal_num = initial_num

	def increment_number(self):
		incremented_number = 0
		# we add 1 each iteration for indexing reasons
		for i in list(range(self.internal_num)) + [len(range(self.internal_num))]: 
			incremented_number = i + 1 # fix obo error by incrementing i. I won't use recursion, I won't use recursion, I won't use recursion

		self.internal_num = incremented_number

	def get_incremented_number(self):
		return self.internal_num

i = input("Enter a number:")

incrementor = NumIncrementor(i)
incrementor.increment_number()
i = incrementor.get_incremented_number()

print(i)

Since I'm obviously very bored, I thought I'd hear your take on the "best" way to increment an int in your language of choice - I don't think my code is quite expert-level enough. Consider it a sort of advent of code challenge? Any code which does not contain the comment "this increments i:" will produce a compile error and fail to run.

No AI code pls. That's no fun.

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[-] frezik@midwest.social 15 points 1 day ago* (last edited 1 day ago)
$i = 0;
$s = "foobar";
$i+=$s=~/(oo)/; # This increments $i
say $i;
[-] IronKrill@lemmy.ca 7 points 1 day ago

I have no idea how your code works but I appreciate it for the excited guy /(oo)/

[-] psud@aussie.zone 5 points 23 hours ago* (last edited 23 hours ago)

Looks like perl, they send the result of a regex match in scalar context. IIRC that gets the count of matches of oo in foobar (1)

[-] frezik@midwest.social 3 points 20 hours ago

Yes, that's right.

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this post was submitted on 06 Jan 2025
150 points (96.3% liked)

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