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counting (lemmy.world)

submitted 1 year ago by hairinmybellybutt@lemmy.world to c/programmerhumor@lemmy.ml

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[-] 30p87@feddit.de 4 points 1 year ago

One hand would be 2**5 = 32 (0 to 31) and two would be 2**10 = 1024 (0 to 1023).

And if you use 3 states per finger (down, half raised and raised), you can have 3**10 = 59049 (0 to 59048).

[-] Cethin@lemmy.zip 2 points 1 year ago

I don't count to 1024 over often (literally never) so I don't feel the need to go to trinary.

[-] LudwigvanBeethoven@sh.itjust.works 1 points 1 year ago

nah, you can have 16+8+4+2+1 = 31 on one hand, and 1024+512+256+128+64+32+16+8+4+2+1=2047 on two hands.

this post was submitted on 21 Nov 2023

422 points (94.0% liked)

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