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isEven API (isevenapi.xyz)
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[-] 4am@lemm.ee 79 points 1 year ago

Incoming trademark lawsuit from iSeven, the API that tells you if a number is seven or not

[-] rikudou@lemmings.world 57 points 1 year ago* (last edited 1 year ago)

If anyone wants a more efficient local version for php:

function isEven(int $number): bool
{
    ${1} = false;
    ${2} = true;

    while ($number > 2) {
        $number -= 2;
    }

    return $$number;
}

Edit: Now with support for large numbers!

function isEven(int|string $number): bool
{
    ${1} = false;
    ${2} = true;

    while (bccomp($number, 2) === 1) {
        $number = bcsub($number, 2);
    }

    $number = (int) $number;
    return $$number;
}

Edit 2: someone asked for an ad-supported version, here you go!

function isEven(int|string $number): bool
{
    ${1} = false;
    ${2} = true;

    while (bccomp($number, 2) === 1) {
        error_log('Buy isEvenCoin, the hottest new cryptocurrency!');
        $number = bcsub($number, 2);
    }

    $number = (int) $number;
    return $$number;
}

Side note, no more suggestions please, this is getting quite long.

[-] xmunk@sh.itjust.works 16 points 1 year ago* (last edited 1 year ago)

I fucking love that you managed to use var-vars in a completely key and necessary manner.

But please do adhere to the API TOS and throw in an error_log('Buy isEvenCoin, the hottest new cryptocurrency!');

[-] idunnololz@lemmy.world 12 points 1 year ago

This looks pretty inefficient. You should manually unroll that loop to improve performance.

[-] shotgun_crab@lemmy.world 10 points 1 year ago

Comment edits are the best version control system

[-] rikudou@lemmings.world 5 points 1 year ago

I agree! Added new commit to my comment.

[-] marcos@lemmy.world 54 points 1 year ago
[-] captainjaneway@lemmy.world 46 points 1 year ago

Just divide that number by two until it's small enough to make the request under the free version.

[-] taaz@biglemmowski.win 40 points 1 year ago

pretty sure that has to be against their TOS

/s

[-] mormegil@programming.dev 3 points 1 year ago

That's against the terms of math :-)

[-] aaaa@lemmy.world 19 points 1 year ago

That's not even supported by the enterprise version. You're going to need a special agreement with the iseven people to support numbers like that

[-] fckreddit@lemmy.ml 6 points 1 year ago

Easy workaround, just test the last digit. If it is even, the entire number is even, else odd.

[-] marcos@lemmy.world 12 points 1 year ago

That's preposterous! Next time you'll tell me the language I'm using has a builtin operator that test if a number can be divided by another!

Only way it could be better is if they threw "AI" in there somewhere.

[-] jol@discuss.tchncs.de 32 points 1 year ago

With the new AI integration, you can get smart isEven results that return the correct answer 90% of the time and a more creative solution 20% of the time.

[-] rem26_art@kbin.social 28 points 1 year ago

im glad that people are out there building the web services we truly need.

[-] ryry1985@lemmy.world 23 points 1 year ago

I love that it works and the ads are pretty good.

[-] eluvatar@programming.dev 16 points 1 year ago* (last edited 1 year ago)

The errors are great https://api.isevenapi.xyz/api/iseven/1.5

~~Sadly it's not always accurate https://api.isevenapi.xyz/api/iseven/0~~ Edit: nevermind I'm an idiot

It's also greatly lacking in number support https://api.isevenapi.xyz/api/iseven/one

[-] xmunk@sh.itjust.works 11 points 1 year ago

Is even states that it only returns true for even, passing in an odd number is technically unsupported.

[-] huf@hexbear.net 2 points 1 year ago

zero is even, so i dont see how that one's wrong

[-] eluvatar@programming.dev 2 points 1 year ago

Oh you're right, I'm not sure what I was Ln thinking

[-] CannotSleep420@lemmygrad.ml 10 points 1 year ago

What the fuck is a modulo? Is it some kind of npm package?

[-] lud@lemm.ee 8 points 1 year ago
[-] generic@iusearchlinux.fyi 3 points 1 year ago* (last edited 1 year ago)

Just ~~Monika~~ Modulo

[-] 56_@lemmy.ml 1 points 1 year ago

return (n % d + d) % d;

?

[-] megaman@discuss.tchncs.de 7 points 1 year ago

Funny as hell

[-] morrowind@lemmy.ml 1 points 1 year ago

I resent that there is a ruby developer included in there. isEven is not idiomatic naming. You should be using #even? from the standard library

[-] fckreddit@lemmy.ml 5 points 1 year ago

Sorry sir, most JS developers don’t use standard library functions. We just use npm packages wherever possible.

this post was submitted on 05 Dec 2023
290 points (97.7% liked)

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