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submitted 1 day ago* (last edited 1 day ago) by Melatonin@lemmy.dbzer0.com to c/asklemmy@lemmy.ml

How about ANY FINITE SEQUENCE AT ALL?

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[-] ped_xing@hexbear.net 6 points 20 hours ago

The conclusion does not follow from the premises, as evidenced by my counterexample. It could be the case that every finite string of digits appears in the decimal expansion of pi, but if that's the case, a proof would have to involve more properties than an infinite non-repeating decimal expansion. I would like to see your proof that every finite string of digits appears in the decimal expansion of pi.

[-] BrainInABox@lemmy.ml -3 points 20 hours ago

Well that's just being pointlessly pedantic, obviously they fucking know that a repeating number of all zeros and ones doesn't have a two in it. This is pure reddit pedantry you're doing

[-] ExFed@lemm.ee 5 points 19 hours ago
this post was submitted on 26 Dec 2024
197 points (98.5% liked)

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