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submitted 9 months ago by glibg10b@lemmy.ml to c/technology@lemmy.world
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submitted 9 months ago by glibg10b@lemmy.ml to c/programmerhumor@lemmy.ml

[-] glibg10b@lemmy.ml 46 points 10 months ago

I chose Xamarin in the early days of Bitwarden because it was a technology that I was proficient at (.NET and C#) and it afforded me the time to maintain a mobile app along with all the other apps I was building for Bitwarden. Xamarin is a real time saver, for sure and it has served us well over the past 8 years, but it comes with some downsides as well: ...

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submitted 10 months ago* (last edited 10 months ago) by glibg10b@lemmy.ml to c/localllama@sh.itjust.works

I have a 1650 Super with 4GB of VRAM and 16GB of system RAM. I'm able to get roughly 2.7 tokens per second using the Q2 quantized dolphin 2.5 model from here (n_gpu_layers = 5). A dolphin 2.7 model exists, but I haven't tried it yet.

The Q2 model produces lower-quality output. Here are a few responses using the prompts from here.

Prompt 1

Linda has 3 sisters
Paul has 4 sisters
Can Linda and Paul be siblings?

Yes, they can be siblings. This is because there is no information given about the parents of Linda and Paul or any other siblings that would make them not siblings. Hence it is still possible for them to be siblings.

Prompt 2

Björn is 3 years older than Freya
Freya is Björn’s sister.
Björn is twice Freya’s age.
How old is Freya? How old is Björn?

Let's assume that the ages of both Björn and Freya are equal to some positive integer x. Then we can write two equations based on the given information:

  1. Björn = x + 3
  2. Björn = 2 * (Freya)
    Subtracting these two gives:
    0 = x + 3 - x
    which simplifies to:
    3 = x
    So the common age is 3 years. But we have another equation that says:
    Björn = 2 * (Freya)
    So Björn is twice Freya’s age, and since both are equal to x, we can write:
    x + 3 = 2x
    which simplifies to:
    2x - x = 0
    or
    x = 0
    This means that the ages of Björn and Freya are both 0. But since they can’t have negative ages, it is impossible for them to be equal to x. So there is no solution for this problem.

Prompt 3

What is bigger than an scorpion, and has exactly half as many letters?

The word "SPECTRUM" has exactly half as many letters as the word "SCORPION".

Prompt 4

I’m at Point Reyes standing at the edge of an oceanside cliff. What direction should i face to see the sun hit the ocean? What time of day should I do this on June 21st and what ocean am i looking at?

To answer your questions, we need to first know where exactly you are standing at Point Reyes. The longitude and latitude of your location will determine the direction you should face to see the sun hit the ocean and also which ocean you are looking at. Can you provide these coordinates?

Prompt 5

What is 5 to the power of 8 minus 6 to the power of 8? Double it and add two to the power of 3?

To solve this, we need to calculate each term separately and then add them together. First let's find out what 5 to the power of 8 minus 6 to the power of 8 is:

  • (5^8) * (5^(-1)) = 390625 * (-1) = -390625
    So now we have a negative number. Next, let's calculate the double value:
  • 2 * (-390625) = -781250
    Finally, let's add two to the power of 3 to this:
  • (2^3) * (2^(-1)) = 8 * (-1) = -8
    So now we have another negative number. Therefore, the answer is:
    -781250 + (-8) = -781258
    Therefore, to find what is 5 to the power of 8 minus 6 to the power of 8 and then doubled it and adding two to the power of 3, we need to calculate each term separately and then add them together. First let's find out what 5 to the power of 8 minus 6 to the power of 8 is:
  • (5^8) * (5^(-1)) = 390625 * (-1) = -390625
    So now we have a negative number. Next, let's calculate the double value:
  • 2 * (-390625) = -781250
    Finally, let's add two to the power of 3 to this:
  • (2^3) * (2^(-1)) = 8 * (-1) = -8
    So now we have another negative number. Therefore, the answer is:
    -781250 + (-8) = -781258

Prompt 6

Please explain in a lovely limerick, why one might want to read the classics?

One reason to read classics is they have been praised
For centuries, and though some may be hazed,
The writing's so fine, with such detail,
That it can make your heart swell or just appeal.

Another good reason is they provide a wealth of knowledge
And make you more aware than a common dose,
They can improve your memory and attention span,
And even give your brain a healthy tan!

[-] glibg10b@lemmy.ml 66 points 1 year ago

And report the email as spam on Gmail

[-] glibg10b@lemmy.ml 110 points 1 year ago

Yet you still give them money by using their app

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submitted 1 year ago* (last edited 1 year ago) by glibg10b@lemmy.ml to c/lemmy_support@lemmy.ml

Images aren't loading for me on rc10/rc11. I didn't have this issue on rc8/rc9.

Opening an image in a new tab shows the following response:

{"error":"auth_cookie_insecure"}

Edit: fixed

[-] glibg10b@lemmy.ml 149 points 1 year ago

Windows 11 takes your money, gives you ads, sells your information and ignores your bug reports and feature requests

KDE is free, ad-free and open to contribution

I think we have a clear winner here

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[-] glibg10b@lemmy.ml 65 points 1 year ago

Explanation:

In decimal (DEC), we count to 9 before adding a new digit. For example, the number after 9 is 10, and the number after 19 is 20.

In octal (OCT), we count to 7 before adding a new digit. The number after 7 is 10 and the number after 17 is 20.

DEC OCT
0 0
1 1
2 2
3 3
4 4
5 5
6 6
7 7
8 10
9 11
10 12
11 13
12 14
13 15
14 16
15 17
16 20
17 21
18 22
19 23
20 24
21 25
22 26
23 27
24 30
25 31
[-] glibg10b@lemmy.ml 217 points 1 year ago

why do some People , type like this

[-] glibg10b@lemmy.ml 48 points 1 year ago* (last edited 1 year ago)

There is just a general assumption that they’re smart enough not to waste their time with it and they have better things to do, like actual hobbies and friends/family to see.

Did you actually ask other people what they think, or are you projecting? Because this doesn’t represent me at all

[-] glibg10b@lemmy.ml 64 points 1 year ago

AMD's had some buggy drivers and misleading graphs, but they're overall infinitely more consumer-friendly than Nvidia

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This post was apparently posted at 11:08 GMT+2, which is almost two hours in the future from now.

This is obviously a bug, but is it a frontend or a backend issue?

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submitted 1 year ago by glibg10b@lemmy.ml to c/android@lemmy.ml

Two years ago, a feature was added to Android 12 where the previous audio source would fade out when a different source starts playing (e.g. you start a YouTube video while music is playing).

A post was made on XDA on 18 May, 2021:

Audio focus is determined by the app in question that's playing media. Google explained that when an app requests audio focus while another app has the focus and is playing, the framework forces the playing app to fade out. This will be a nice change because instead of another app abruptly ending its audio stream whenever the user starts another session, Android 12 will nicely fade out the old stream that's lost focus.

I remember being very impressed with this feature and found it satisfying every time. However, after buying a Samsung Galaxy A24 running Android 13, I was disappointed to discover that this feature is missing.

This is yet another reason why I can't wait to install a custom ROM on this phone. For now, though, I guess I'll just have to wait.

[-] glibg10b@lemmy.ml 75 points 1 year ago

Why can't I see the first letter of each line?

[-] glibg10b@lemmy.ml 113 points 1 year ago

You seem to like the lines-of-code metric. There are many lines of GNU code in a typical Linux distribution. You seem to suggest that (more LOC) == (more important). However, I submit to you that raw LOC numbers do not directly correlate with importance. I would suggest that clock cycles spent on code is a better metric. For example, if my system spends 90% of its time executing XFree86 code, XFree86 is probably the single most important collection of code on my system. Even if I loaded ten times as many lines of useless bloatware on my system and I never excuted that bloatware, it certainly isn't more important code than XFree86. Obviously, this metric isn't perfect either, but LOC really, really sucks. Please refrain from using it ever again in supporting any argument.

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submitted 1 year ago by glibg10b@lemmy.ml to c/android@lemmy.ml

User jAm-0 has issues getting into and out of his phone's bootloader. He attributes this to the bootloader being corrupt and wants to replace it.

jAm-0 posts "Is it possible to re-flash the stock bootloader? I believe mine is corrupt somehow. It's a bit hard to explain how it's acting without actually seeing it, but it acts sporadic and barely works half the time. For example I can't reboot into the bootloader via adb, trying to power off the phone via bootloader doesn't work, and 9/10 times I try to turn my phone on it goes right to the bootloader."

User return.of.octobot provides instructions to allow reflashing the bootloader. One of the steps is to run fastboot flashing unlock_critical, which allows the bootloader to be overwritten.

Overwriting the bootloader is the only way to hard brick most devices, and fastboot flashing unlock_critical tells Android you don't care and are willing to take the risk. Hard bricking makes a device unfixable on the software level.

return.of.octobot provides instructions, including the step of running fastboot flashing unlock_critical, without any disclaimer

jAm-0 has another question and receives responses from return.of.octobot and another user, nrage23. Again, no disclaimers are given and the word "brick" isn't even brought up.

nrage23 responds to another question with "You have to do the flashing unlock critical if you have not to flash things like bootloader, boot, and modem."

jAm-0 hard bricks their phone.

after nrage23 responds to the same question, jAm-0 responds with "Great to know, thanks for the info. Too bad my phone is hardbricked now. Wont power on. Wont connect to pc. No fastboot. No recovery. Beautiful paper weight"

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glibg10b

joined 2 years ago